Then due to this high open loop gain, the output from the comparator swings either fully to its positive supply rail, +Vcc or fully to its negative supply rail, -Vcc on the application of varying input signal which passes some preset threshold value. Voltage comparators on the other hand, either use positive feedback or no feedback at all (open-loop mode) to switch its output between two saturated states, because in the open-loop mode the amplifiers voltage gain is basically equal to A VO. We have also seen that the standard operational amplifier is characterised by its open-loop gain A O and that its output voltage is given by the expression: V OUT = A O(V+ – V-) where V+ and V- correspond to the voltages at the non-inverting and the inverting terminals respectively. We have seen in previous tutorials that the operational amplifier can be used with negative feedback to control the magnitude of its output signal in the linear region performing a variety of different functions. In other words, the op-amp voltage comparator compares the magnitudes of two voltage inputs and determines which is the largest of the two. As a result, output line 7 is driven LOW.The Op-amp comparator compares one analogue voltage level with another analogue voltage level, or some preset reference voltage, V REF and produces an output signal based on this voltage comparison. The input at the 1, 2, 4, 8 inputs to a 4-line to 16-line decoder with active- low outputs is 1110.How many outputs would two 8-line-to-3-line encoders, expanded to a 16-line-to-4-line encoder, have?.Which output goes LOW when the inputs are 1001? A certain BCD-to-decimal decoder has active-HIGH inputs and active- LOW outputs.For the device shown here, assume the D input is LOW, both S inputs are HIGH, and the input is HIGH.
Which of the following logic gives the complementary outputs?.MULTIPLEXER, ARE CONNECTED TOGETHER THROUGH A 4-INPUT
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